y-[y-(3-y)]=10y+[(y+2)-(y+1)]

Solution for y-[y-(3-y)]=10y+[(y+2)-(y+1)] equation:

Simplifying
y + -1[y + -1(3 + -1y)] = 10y + [(y + 2) + -1(y + 1)]
y + -1[y + (3 * -1 + -1y * -1)] = 10y + [(y + 2) + -1(y + 1)]
y + -1[y + (-3 + 1y)] = 10y + [(y + 2) + -1(y + 1)]

Reorder the terms:
y + -1[-3 + y + 1y] = 10y + [(y + 2) + -1(y + 1)]

Combine like terms: y + 1y = 2y
y + -1[-3 + 2y] = 10y + [(y + 2) + -1(y + 1)]
y + [-3 * -1 + 2y * -1] = 10y + [(y + 2) + -1(y + 1)]
y + [3 + -2y] = 10y + [(y + 2) + -1(y + 1)]

Reorder the terms:
3 + y + -2y = 10y + [(y + 2) + -1(y + 1)]

Combine like terms: y + -2y = -1y
3 + -1y = 10y + [(y + 2) + -1(y + 1)]

Reorder the terms:
3 + -1y = 10y + [(2 + y) + -1(y + 1)]

Remove parenthesis around (2 + y)
3 + -1y = 10y + [2 + y + -1(y + 1)]

Reorder the terms:
3 + -1y = 10y + [2 + y + -1(1 + y)]
3 + -1y = 10y + [2 + y + (1 * -1 + y * -1)]
3 + -1y = 10y + [2 + y + (-1 + -1y)]

Reorder the terms:
3 + -1y = 10y + [2 + -1 + y + -1y]

Combine like terms: 2 + -1 = 1
3 + -1y = 10y + [1 + y + -1y]

Combine like terms: y + -1y = 0
3 + -1y = 10y + [1 + 0]
3 + -1y = 10y + [1]
3 + -1y = 10y + 1

Reorder the terms:
3 + -1y = 1 + 10y

Solving
3 + -1y = 1 + 10y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-10y' to each side of the equation.
3 + -1y + -10y = 1 + 10y + -10y

Combine like terms: -1y + -10y = -11y
3 + -11y = 1 + 10y + -10y

Combine like terms: 10y + -10y = 0
3 + -11y = 1 + 0
3 + -11y = 1

Add '-3' to each side of the equation.
3 + -3 + -11y = 1 + -3

Combine like terms: 3 + -3 = 0
0 + -11y = 1 + -3
-11y = 1 + -3

Combine like terms: 1 + -3 = -2
-11y = -2

Divide each side by '-11'.
y = 0.1818181818

Simplifying
y = 0.1818181818